When to usage R = 0.082 vs R = 8.314Anyone have actually a rapid kinda way to memorize/know once to use either that these?So far in my evaluation I"ve mainly only been making use of the R = 0.082, yet I did have actually 1 difficulty come up whereby R = 8.314 instead.

You are watching: When to use 8.314 or 0.08206 Look in ~ the systems for the best gas constant. R = 0.082 has actually units that (L atm)/(mol K), conversely, R = 8.314 has units that J / (mol K). If the question has actually pressure and also volume to express in systems of atm and also liters respectively, you usage the R = 0.082 value. If the pressure is express in pascals and also volume in cubic meters, you use R = 8.314 value (same if push is to express in kilopascals and also volume in liters, due to the fact that 1 kPa = 1000 Pa and also 1 together = 1/1000 m^3).The 2 R values are the very same thing but the factor for the differences is because of having different units. R = 8.314 is actually the much more important value since it is to express in SI systems (note the 1 J = 1 Pa * m^3= 1 N/m^2 * m^3 = 1 N * m).
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Look in ~ the systems for the ideal gas constant. R = 0.082 has units of (L atm)/(mol K), conversely, R = 8.314 has units of J / (mol K). If the question has actually pressure and volume express in systems of atm and liters respectively, you usage the R = 0.082 value. If the push is expressed in pascals and also volume in cubic meters, you use R = 8.314 worth (same if pressure is express in kilopascals and volume in liters, since 1 kPa = 1000 Pa and also 1 l = 1/1000 m^3).The two R values space the exact same thing but the reason for the differences is due to having various units. R = 8.314 is in reality the more important value because it is expressed in SI devices (note the 1 J = 1 Pa * m^3= 1 N/m^2 * m^3 = 1 N * m).

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Just remember the you can easily convert in between the 2 if you just remember a few constants.Just remember as soon as you perform the trouble your systems will matter, so if you execute a fast unit-cancelling you will understand if you supplied the ideal one or the dorn one.For instance if they want you to solve for pressure, then p = nRT/V won"t cancel devices using 8.314 J/(mok*K). You"ll finish up through P = X Joules/Liter
Reactions:1 user Just remember the you can easily convert between the two if you just remember a couple of constants.Just remember once you do the difficulty your devices will matter, for this reason if you perform a rapid unit-cancelling you will recognize if you provided the best one or the dorn one.For circumstances if they desire you to fix for pressure, then ns = nRT/V won"t cancel devices using 8.314 J/(mok*K). You"ll finish up with P = X Joules/Liter
The units do cancel with joules/liter. A joule is a unit the work, which because that gases is simply pressure * volume. 1 J = 1 Pa * m^3 = 1 kPa * 1 L. For this reason 1 joule / liter = 1 kPa * together / l = 1 kPa.The only time R = 0.082 is supplied is as soon as the push is to express in atm and volume in liters. R = 8.314 is a much an ext common and important value when pressure and also volume are expressed in SI units, even if it is Pa and m^3 or kPa and also L. The 8.314 J/(mol K) particularly links between complimentary energy and temperature, i m sorry is why in equations like G = -RTln(K), you usage R = 8.314 J/(mol K).Also the two R values are tantamount as watched by the following:0.082 l atm/(mol K) * 101325 Pa/1 atm * 1 m^3/1000 l * 1 J/(Pa * m^3) = 0.082 * 101.325 J/(mol K) = 8.31 J / (mol K). It simply helps to understand both since of time constraints in the MCAT.