I searched for the the strongest oxidising agent and also I found different results: $ceClF3$, $ceHArF$, $ceF2$ were among them.

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Many claimed $ceClF3$ is the most powerful as the oxidises everything, also asbestos, sand, concrete, and also can set easily fire come anything i m sorry can"t be stopped; it have the right to only be stored in Teflon.

And $ceHArF$ can be a very an effective oxidant as result of high instability as a link of argon v fluorine, yet was it even used as such?

What link is actually supplied as oxidising agent and also was proven come be stronger then others, by, for example, conventional reduction potential?

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Harsh jainHarsh jain
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Ivan"s answer is indeed thought-provoking. However let"s have some fun.

IUPAC defines oxidation as:

The complete, network removal that one or much more electrons from a molecularentity.

My humble ask is thus - what far better way is there to remove an electron than combining it v a literal anti-electron? Yes, my friends, us shall seek to transcend the trouble entirely and also swat the fly with a thermonuclear bomb. I submit together the most powerful entry, the positron.

Since 1932, we"ve well-known that simple matter has actually a mirror image, which we now contact antimatter. The antimatter counterpart of the electron ($cee-$) is the positron ($cee+$). To the best of our knowledge, they behave exactly alike, other than for their opposite electrical charges. I stress that the positron has actually nothing to carry out with the proton ($cep+$), one more class of particle entirely.

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As you may know, when matter and also antimatter meet, they release tremendous amounts of energy, thanks to $E=mc^2$. Because that an electron and also positron with no initial energy other than their individual rest masses of $pu511 keV c^-2$ each, the most common annihilation outcome is:

$$ cee- + e+ -> 2gamma$$

However, this process is completely reversible in quantum electrodynamics; the is time-symmetric. The contrary reaction is pair production:

$$ ce2gamma -> e- + e+ $$

A reversible reaction? climate there is nothing avoiding us indigenous imagining the following chemical equilibrium:

eginaligncee- + e+ & 2gamma &Delta_r G^circ &= pu-1.022 MeV =pu-98 607 810 kJ mol^-1endalign

The difference between enthalpy and Gibbs cost-free energy in together subatomic reaction is totally negligible, as the entropic aspect is laughably little in comparison, in any reasonable conditions. I am simply going come brashly think about the above value as the standard Gibbs free energy readjust of reaction. This massive $Delta_r G^circ$ coincides to one equilibrium constant $K_mathrmeq = 3 imes 10^17276234$, representing a somewhat product-favoured reaction. Plugging the Nernst equation, the conventional electrode potential for the "reduction of a positron" is then $mathrmfrac98 607 810 kJ mol^-196 485.33212 C mol^-1 = +1 021 998 V$.

Ivan mentions in his answer making use of an alpha fragment as an oxidiser. Let"s take the further. Follow to NIST, a stormy estimate for the electron affinity of a totally bare darmstadtium cell core ($ceDs^110+$) is $pu-204.4 keV$, so also a stripped superheavy atom can"t complement the oxidising strength of a positron!