nitrogen gas is specify as N2. That moleculer massive will come to be 28. For its one mole it is the 28gram. Follow to mole principle in one mole there is 6.022*10^23 moles room present. For this reason mass that 1 molecule of nitogen gas is 28/(6.022*10^23) gram. Solve it and u will acquire answer.

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Actually massive of 1 atom of nitrogen is 14 u(u=atomic fixed unit) fixed of 1 mole=mass that 1 atom that nitrogen * Avagadro"s no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm

1 mole of Nitrogen has 28 g mass. Together Nitrogen gas is made up of two Nitrogen aspects Each nitrogen has Atmoic fixed 14 g so N2 will have actually 2x14 = 28 g.

As we know that no. Of moles = provided mass/molar mass likewise no. Moles = no.of particles(atoms,molecules etc)/avogadro no.(No) as we understand Avogadro"s number=6.023*10^23 so no. Of moles=1/6.023*10^23 molar mass of nitrogen = 14*2=28 so no. Of mole = mass/28 1/6.023*10^23=mass/28 mass=28/6.023*10^23...

Nitrogen always exists together a dimer therefore the mass of the molecule is to be calculated by multiplying atom mass that nitrogen through 2 which method 14*2=28
Nitrogen molecule mass is 28 1mole of n2 is 28gram for 1molecule of nitrogen division 28by avagadro number 6.022 10^23 therefore ans will certainly be 28/6.022 10^23=4.64 10^-23
14 grams fixed = variety of moles x molar fixed 1 mole= relative mass in grams that that details element
mass the 1 mole=mass that 1 atom that nitrogen * Avagadro"s no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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