2,092 J is the quantity of heat energy released when 50.0 grams the water is cooled.

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Explanation:

Mass of water = m = 50.0 g

Initial temperature of the water =

Final temperature of the coffee =

Specific warm of water = c = 4.184 J/g°C

Heat required to cooled from 20°C come 10°C= Q

Q = -2,092 J

Negative sign means that power is lost.

2,092 J is the lot of heat energy released once 50.0 grams the water is cooled.

The amount of warmth released as soon as 50 g of water cooled native 20°C come 10°C will certainly be equal to - 2093 J.

Explanation:

Given data:

Mass the water = 50 g

Initial temperature= T1 = 20°C

Final temperature= T2 = 10°C

Specific warm of water= c = 4.186 J/g. °C

Amount of warmth released = Q= ?

Solution:

Formula:

Q = m. C. ΔT

ΔT = T2 - T1

ΔT = 10°C - 20°C

ΔT = -10°C

Now we will put the values in formula.

Q = m. C. ΔT

Q = 50 g . 4.186 J/g. °C . -10°C

Q = - 2093 J

The amount of warmth released as soon as 50 g of water cooled indigenous 20°C to 10°C will be equal to - 2093 J.

Q = mc Δtq= heat, m = fixed (in grams), c=specific warm (4.18 J/°C * g or J/K * g for water), Δt = readjust in temperature (in kelvin)For this equation:q = ?, m = 50.0 g, c = 4.18 J/°C *g = 4.18 J/K *g, early t = 20.0°C, last t = 10°CTo convert from °C to K, include 273 to °C0°C = 273 KInitial t = 20.0°C + 273 = 293 KFinal t = 10.0°C + 273 = 283 KΔT = last temperature - initial temperature = 283-293 = -10 KPlug in what you know:q = (50.0 g) x (4.18 J/K * g) x (-10 K) = -2090Check sig figs and cancel out units: -2090 J (you need 3 sig figs from the initial numbers given and also the units space Joules because grams and Kelvin cancel out)Check to make sure answer makes sense:Since heat power is released, the answer have to be negative. The price is an unfavorable and therefore, renders sense

q = mC∆T

q = (50 g)(4.184 J/g/deg)(10 deg)

q = 2092 J = 2.09x10^3 J

That"s how it"s done.

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Explanation:

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For the complying with dehydrohalogenation (e2) reaction, draw the zaitsev product(s) result from elimination involving c3â€“c4 (i. E., the carbon atoms shown with stereobonds). Display the product stereochemistry clearly. If there is more than one essential product, both assets may be drawn in the same box. Overlook elimination involving c3 or c4 and any carbon atom various other than c4 or c3.