You are watching: If the diels-alder reaction between dimethylmaleic anhydride
explain why one molecule that NaBH4 will reduce only two molecules that m-acetylbenzaldehyde to form the equivalent product
NaBH4 is a gentle reducing agent and will only alleviate aldehydes and ketones. Also, one molecule used as the substrate will need 2 hydride ion for reduction, therefore NaBH4 can only alleviate 2 molecules because of only having 4 hydride ions.
because benzopinacol and benzopinacolone have practically identical melt points, explain (no spec.) just how you could prove the samples the the 2 compounds room different
A TLC test can be used to prove that they are different from their RF values, due to the fact that they have virtually identical melt points.
Describe any important differences in between benzopinacol and benzopinacolone in the IR, H NMR and C NMR spectra.
the difference between them in Ir would certainly be the broad OH peak in 3200-3400 being changed by a carbonyl peak at 1720 range. Because that H NMR there will be no oh signal or CH-OH signal.
In its IR spectrum, a disubstituted aromatic compound proved a strong absorption at 740 cm-1. To be the link ortho-, meta-, or para-?
the IR screens a optimal at 740 cm-1, i beg your pardon is within the selection of 735-770 cm-1 that suggests that the fragrant compound is ortho- substituted.
A phase-transfer catalyst is offered when methoxybenzyl alcohol is oxidized through NaOCl, because methoxybenzyl alcohol is soluble in organic solvents, except water. However, NaOCl is dissolve in H2O however not in essential solvents. The catalyst helps by facilitating a reaction to occur.
why is it vital that the number of moles the methoxide ion need to be the same as the variety of moles that p-acetamidophenol provided for Williamson synthesis of phenacetin?
it have to be an equal amount the moles because that both because methoxide help deprotonate p-acetamindophenol. If not, hen some of the p-acetamidophenol will certainly not be protonated and form phenacetin. If too much it will compete with p-acetamidophenoxide ion.
If phenacetin "oils out" of solution throughout a recrystallization, what remedial activity should be taken?
if phenacetin "oils out" during recrystallization, then an ext ethanol must be included to the solution following reheating come redissolve the solution and won"t oil out. This permits vacuum filtration be preformed.
the product needs to be distilled slowly in order for decoupling to happen at a constant pace. If distillation occurs at a much faster rate, climate it would certainly be harder come handle.
If the Diels-Alder reaction in between dimethylmaleic anhydride and also furan had actually worked, would certainly cantharidin have been formed?
No, the cantharidin would certainly not form since the is the exo product and also the endo product forms instead. Also, the C=C shortcut is absent.
concentrated acids room toxic and also oxidizing. Prevent inhalation, ingestion, and also skin and also eye contact. Handle under fume hood.
explain exactly how mixture melting points can be offered to distinguish in between two compounds v a similar melting points
if 2 different compounds (unknown) space within the selection of a well-known compound"s melt point, then a mixture melting allude can be performed. Mix the known and unknown compound in a capillary tube, the MP selection is tested to recognize if the unknown matches the known MP.
The intermediate created in EAS is a positively fee ammonium ion, while intermediary NAS to produce in negatively charged. Also, EDG stabilize EAS reactions, conversely, EWG stabilize NAS reactions from the means that benzene reacts to them. EAS reacts together a nucleophile cant be electron deficient, NAS the ring acts as an electrophile v withdrawing groups and also increases price of reaction.
Resonance dram a function in both intermediates. In EAS the many stable intermediate is as soon as the optimistic charge is top top the EDG, since all atoms have complete octets. In NAS, the many stable intermediate is when the an unfavorable charge is spread out ~ above non-carbon atoms.
See more: Temperature Is The Measure Of The Average Energy Of Particles In A Substance
Why can you not distinguish between an aldehyde and also a ketone using only the 2,4-dinotrophenylhydrazine reagent?
This happens because both ketones and aldehydes react immediately, which offers a precipitate with 2,4-dinitrophenylhydrazine.
What perform you suppose to see for a hopeful Tollen"s test? Which course of carbonyl compound offers a optimistic test result?
A hopeful test for the Tollen"s test will an outcome in the development of a silver precipitate. When aldehyde is lessened to carboxylic acid and gives off a optimistic result
it is essential when identifying a certain unknown ketone or aldehyde. The derivative is optimistic for a well-known compound , i m sorry is then contrasted to the same test for the unknown compound. Melting allude would be valuable to help in this and if the compounds enhance MPs