Ceq1 unchanged, I copied eight microfarads unchanged, and then this one and a fifty percent microfarads plus Ceq2 will certainly be replaced with C tantamount three. And also so, due to the fact that these space in series, us take the reciprocal of the first, one over one-half, add to the reciprocal of the second, one over 15.75, and then take the sum of those two, and then the reciprocal of that sum, giving us 1.3696 microfarads. Then, the identical capacitance the all three of these is walk to it is in the final answer, or the complete equivalent capacitance. That's walking to it is in Ceq1 to add eight microfarads add to Ceq3. We're walking to simply take the arithmetic amount of them due to the fact that they are in parallel. So, we have 2.0588 microfarads plus eight microfarads plus 1.3696 microfarads, offering us 11.4 microfarads is the total capacitance the the entire circuit.">


You are watching: Find the total capacitance of the combination of capacitors, in microfarads.

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This is college Physics Answers with Shaun Dychko. We"re going to discover the identical capacitance of this entire circuit, and also it"s essential to take it action by action so it doesn"t it seems ~ overwhelming. Now, we"re going to rewrite the circuit as displayed in this chart here, wherein I"ve copied the 1.5 microfarads unchanged. I copied the eight microfarads unchanged. However the distinctions are the I linked these 2 capacitances right into capacitance equivalent one, and then merged these two capacitances into capacitance tantamount two. And also so, the following step would be to combine these two. And also then, the 3rd step will certainly be to incorporate all 3 in parallel. Okay. So, the tantamount capacitance one is going to be the an outcome of this two linked together. And, because they room in series, we take the mutual of every one, include them together, and then take it the mutual of the sum. And also so, this works out to one over five plus one end 3.5, offering us 2.0588 microfarads, keeping lots that decimal places since this is an intermediate in calculation. And then, in the indistinguishable capacitance two, due to the fact that these space in parallel, we can take the straight arithmetic amount of the two capacitances to obtain their equivalent. So, 0.75 add to 15 microfarads provides 15.75 microfarads, and also that"s what"s composed here. Then, we"re going to rewrite this schematic together this one. And, I replicated Ceq1 unchanged, I copied eight microfarads unchanged, and then this one and a fifty percent microfarads add to Ceq2 will be changed with C identical three. And so, because these space in series, us take the reciprocal of the first, one end one-half, to add the mutual of the second, one end 15.75, and also then take the sum of those two, and also then the mutual of the sum, providing us 1.3696 microfarads. Then, the indistinguishable capacitance of all three of these is walking to it is in the final answer, or the total equivalent capacitance. That"s going to it is in Ceq1 add to eight microfarads to add Ceq3. We"re walk to just take the arithmetic sum of them since they are in parallel. So, we have actually 2.0588 microfarads plus eight microfarads plus 1.3696 microfarads, offering us 11.4 microfarads is the full capacitance the the entire circuit.
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