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You are watching: 2so3(g)⇌2so2(g)+o2(g) because that a chemical reaction aA + bB --> cC + dD, the equilibrium consistent is Keq = (C^c*D^d)/(A^a*B^b) wherein A, B, C and also D represent the concentration the A, B, C and D resp.

If because that the reaction 2SO2(g)+O2(g)-->2SO3(g), Keq = 85

=> 85 = SO3^2/(SO2^2*O2)

because that the reaction 2SO3(g)-->2SO2(g)+O2(g)...

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For a chemical reaction aA + bB --> cC + dD, the equilibrium consistent is Keq = (C^c*D^d)/(A^a*B^b) where A, B, C and D represent the concentration the A, B, C and D resp.

If because that the reaction 2SO2(g)+O2(g)-->2SO3(g), Keq = 85

=> 85 = SO3^2/(SO2^2*O2)

For the reaction 2SO3(g)-->2SO2(g)+O2(g) the equilibrium continuous is the inverse of the turning back reaction.

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This offers the required equilibrium continuous as 1/85 = 0.011

The equilibrium constant for 2SO3(g)-->2SO2(g)+O2(g) is 0.011

exactly how will the concentration of the following molecules readjust given this information?The reaction: 2SO2(g)+o2)g)=2SO3(g) Keq=6.51.0 mol of S02,O2 and SO3 are placed in a 1.0 l container

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